Odpowiedź:
s=20m + 400m = 420m = 0,42km
v = 100km/h
v = s/t | *t
s = v * t | : v
t = s/v
t = 0,42km/100km/h = 0,0042h = 0,252min = 15,12s
Odp. Ten autobus potrzebuje 15,12s na pokonanie tego tunelu.
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Odpowiedź:
s=20m + 400m = 420m = 0,42km
v = 100km/h
v = s/t | *t
s = v * t | : v
t = s/v
t = 0,42km/100km/h = 0,0042h = 0,252min = 15,12s
Odp. Ten autobus potrzebuje 15,12s na pokonanie tego tunelu.