nur115883
A. AD²=(1+√5)²-(5+√5-6)² =1+5+2√5-(√5-1)² =6+2√5-(5+1-2√5) =6 +2√5 -6+2√5 =4√5 b. luas =1/2 x (a+b)xt=1/2 (6 + 5+√5)x (1+√5) =1/2 x (11+√5)(1+√5) =1/2 x (11+12√5+5) =1/2 x (16 +12√5) =8 +6√5 cm² c. keliling = AB+BC+CD+DA =(5+√5)+(1+√5)+6+(4√5) =12+6√5
=1+5+2√5-(√5-1)²
=6+2√5-(5+1-2√5)
=6 +2√5 -6+2√5
=4√5
b. luas =1/2 x (a+b)xt=1/2 (6 + 5+√5)x (1+√5)
=1/2 x (11+√5)(1+√5)
=1/2 x (11+12√5+5)
=1/2 x (16 +12√5)
=8 +6√5 cm²
c. keliling = AB+BC+CD+DA
=(5+√5)+(1+√5)+6+(4√5)
=12+6√5