Geometria analityczna. Zadań 7. Proszę o obliczenia do każdego i ewentualne uwagi i komentarze. Za brak któregoś zadania niestety zgłaszam. Pozdrawiam.
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1.
y = 3x + 1
Dana prosta jets prostopadła do drugiej wtedy gdy iloczyn ich wspołczynników jets równy (-1), zatem
odp. B bo 3 * (-1/3) = -1
2.
A = (0, 0 ) B = (-6, -8)
Xa Ya Xb Yb
Xs = (Xa + Xb) / 2 = (0 - 6)/2 = -6/2 = -3
Ys = (Ya + Yb)/2 = (0 - 8)/2 = -8/2 = -4
S = (Xa , Yb)
S = (-3, -4)
odp. D
3.
y = -2x + 3
odp. B bo
9 = -2 * (-3) + 3
9 = 6 + 3
9 = 9
4.
(x - 7)² + (y + 2)² = 5²
x - 7 = 0 y + 2 = 0
x = 7 y = -2
S = (7, -2) i r = 5
odp. D
5.
3 / (5 + 3) = 15 / (15 + x)
3 / 8 = 15 / (15 + x)
3(15 + x) = 8 * 15
15 + x = 8 * 5
x = 40 - 15
x = 25
odp. C
6.
A = (-4, -1) B = (4, 1) C = (1, 4)
a)
|BC| = √[(1 - 4)² + (4 - 1)²] = √[ (-3)² + 3² ] = √ (9 + 9) = 3√2
b)
Xs = (-4 + 4)/2 = 0/2 = 0
Ys = (-1 + 1)/2 = 0/2 = 0
odp. S = (0, 0 )
c)
pr. CB:
B = (4, 1) C = (1, 4)
y = ax + b
1 = 4a + b
4 = a + b
-1 = -4a - b
4 = a + b
-----------------
3 = -3a
a = -1
4 = a + b
4 = -1 +b
b = 5
pr. CB: y = -x + 5
pr. AD _|_ pr. CB
y = ax + b _|_ y = -x + 5 ⇔ a * (-1) = -1
a = 1
y = x + b i A = (-4, -1)
x y
-1 = -4 + b
b = 3
pr. AD : y = x + 3 --------- odpowiedź