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P=5 W
R=?
Dane:
I = 0,8 A natężenie
P = 5 W moc
Szukane:
R = ? opór
z definicji mocy: P = U * I
z prawa Ohma: I = U / R ===> U = I * R
zatem: P = U * I
P = I * R * I
P = I^2 * R / : I^2
R = P / I^2
R = 5 / (0,8)^2
R = 5 / 0,64
R = 7,8125 Ω
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proszę bardzo, pozdrawiam :)