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Δt=4'c
c=0,5 kal/g'c
ditanya= Q=......?
Jawab= Q= m.c.Δt
Q= 20 g X 0,5 kal/g'c X 4'c
Q= 40
= 20 . 0,5 . (0 - (-4))
= 10 . 4
= 40 kal