Question

Garis y=x-3 dan 2x+3y=1 berpotongan di titik...

Answer 1

Y₁ = y₂
x - 3 = (1 - 2x)/3
3x - 9 = 1 - 2x
x = 10
y = 10 - 3 = 7
berpotongan di (10,7)

Answer 2

X -Y = 3 } x 2 --- 2x -2y .= 6 (per 1,2 di+)
2X + 3y .= 1 } x 1 ---- 2x + 3y = 1
mendapat y= 1
dan eliminasi nilai y kedqlaam pers diatas untk mendapatkan nilai x
2x + 3y = 1
2x + 3(-1) = 1
2x = 4
x = 2
jadi (x,y) (2,-1)