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persgaris melalui (6,-1) ---- y+1=m(x-6)---y=mx -6m-1
x²+(mx -6m-1)²-4x+8(mx -6m-1)-5=0
x²+m²x²-2m(6m-1)x +(6m-1)² - 8m x -48m-8-5=0
(1+m²) x² (12m²-2m-8m)x + ((6m-1)² -48m-13)=0
a b c
menyinggung D=b² - 4 ac=0
CARAyang LEBIH MUDAK
cari pusat lingkaran P(-A/2,-B/2) ....... (2, - 4)
garadien darititik pusak ke titik(6,-1) ....m1=(-1+4)/(6-2) =3/4
maka gradien garis singgung tegaklurus m1 . m2=-1 .... 3/4 .m2=-1 ... m3 = -4/3
persamaan garis y-y1=m(x-x1)............y+1==4/3(x-6)
3(y+1)=4x-24
3y+3=4x-24
4x-3y-27=0
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