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t A-C = 4 s
jarak 16 cm
Ditanyakan : A dan f ?
Dijawab :
A = simpangan terjauh = 16/2 = 8 cm
f = 16/4
= 4 Hz
jawaban C
Nomor 13 :
a1 = 0,005 C = 5x10⁻³
q2 = 0,001 C = 1x10⁻³
r = 3 cm = 3x10⁻²
Ditayakan : F ?
Dijawab :
F = k Q1Q2/r²
= 9x10⁹ x 5x10⁻³ x 1x10⁻³/ (3x10⁻²)²
= 9x10⁹ x 5x10⁻⁶ / 9x10⁻⁴
= 5x10⁷ N