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x+2y = 4...........2
eliminasi y dari pers 1 dan 2:
3x-2y = 12
x+2y = 4 (+)
4x = 16
x = 4; maka y = 0
titik potong di (4,0)
x+2y-4= 0
⇒ 3x-2y= 12
3x= 12 -2y= 12
x= 4 y= -6 titiknya (4,-6)
⇒x+2y= 4
x= 4 2y= 4
y= 2 titiknya (4,2)
titik potongnya adalah (4,0)
bukti;
3x-2y= 12
x+2y= 4
----------------- +
4x= 16
x= 4
x+2y= 4
4+2y= 4
2y= 0
y= 0