Tolong di bantu 200gr es bersuhu 0°c di masukkan ke dlm 400 gr air yg bersuhu 100°c.dlm ke adaan setimbang tentukan suhu campuran tersebut . ( C es = 0,5kal/g°c , C air =1 kal/g°c .dan L=80 kal/g) trms
Handrata01
Q lepas = Q terima 200 g x 0,5 kal/gC x (tC-0) = 400 g x 1 kal/gC x (100-tC) 100 kal/C x (tC-0) = 400 kal/C x (100-tC) 100tc- 0 = 40000 - 400tc 500 tc = 40000C tc = 80C
200 g x 0,5 kal/gC x (tC-0) = 400 g x 1 kal/gC x (100-tC)
100 kal/C x (tC-0) = 400 kal/C x (100-tC)
100tc- 0 = 40000 - 400tc
500 tc = 40000C
tc = 80C