3(4+(6−2))+[3²−(6−2)]−(7−5)
=3(4+4)+[3²−(6−2)]−(7−5)
=(3)(8)+[3²−(6−2)]−(7−5)
=24+[3²−(6−2)]−(7−5)
=24+9−(6−2)−(7−5)
=24+9−4−(7−5)
=24+5−(7−5)
=29−(7−5)
=29−2
=27
espero que te sirva suerte!!!!
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✨RESPUESTA✨
=27
EXPLICACIÓN PASO A PASO
3(4+(6−2))+[3²−(6−2)]−(7−5)
=3(4+4)+[3²−(6−2)]−(7−5)
=(3)(8)+[3²−(6−2)]−(7−5)
=24+[3²−(6−2)]−(7−5)
=24+9−(6−2)−(7−5)
=24+9−4−(7−5)
=24+5−(7−5)
=29−(7−5)
=29−2
=27
espero que te sirva suerte!!!!