Question

F(x)=sin x(2+cos x),,,f'(45 derajat)????

Answer 1

F(x) = U x V U = sin x => U' = cos x V = 2 + cos x => V' = - sin x F(x) = U x V F'(x) = U' x V + V' x U F'(x) = (cos x)(2 + cos x) + (- sin x)(sin x) F'(x) = (2 cos x + cos^2 x) + (-sin^2 x) F'(x) = 2 cos x + (cos x)^2 - (sin x)^2 F'(45) = 2 cos 45 + (cos 45)^2 - (sin 45)^2 F'(45) = 2(0,5 akar2) + (0,5 akar2)^2 - (0,5 akar2)^2 F'(45) = akar2 + 0 F'(45) = akar2