f(x) = ax + b
f(-5) = a.(-5) + b = -3
-5a + b = -3
f(1) = a.(1) + b = -9
a + b = -9
a = -9 - b
Disubtitusi :
-5.(-9 - b) + b = -3
45 + 5b + b = -3
45 + 6b = -3
6b = -3 - 45
6b = -48
b = -8
a + (-8) = -9
a = -9 + 8
a = -1
f(x) = -x-8
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Kelas = VIII SMP
Materi = Fungsi
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Penyelesaian:
f (x) = ax + b
• f (- 5)
= - 5a + b = - 3 ......... (1)
• f (1)
= a + b = - 9 ............ (2)
✏Eliminasi b
- 5a + b = - 3
a + b = - 9
_________ _
- 6a = 6
a = 6/- 6
a = - 1
✏Substitusi a
a + b = - 9
- 1 + b = - 9
b = - 9 + 1
b = - 8
✏Rumus fungsi
f (x) = ax + b
f (x) = - 1x + (- 8)
f (x) = - x - 8
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Semoga Membantu ^^
f(x) = ax + b
f(-5) = a.(-5) + b = -3
-5a + b = -3
f(1) = a.(1) + b = -9
a + b = -9
a = -9 - b
Disubtitusi :
-5a + b = -3
-5.(-9 - b) + b = -3
45 + 5b + b = -3
45 + 6b = -3
6b = -3 - 45
6b = -48
b = -8
a + b = -9
a + (-8) = -9
a = -9 + 8
a = -1
f(x) = -x-8