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maka
f '(x) = 3x³⁻¹ - 2.6x²⁻¹ + 9 + 0
f '(x) = 3x²-12x + 9
maka
f ''(x) = 2.3x - 12 + 0
f ''(x) = 6x - 12
Jadi
f ''(2) = 6(2) - 12 = 12 - 12 = 0
Jadi nilai dari f ''(2) adalah 0