Funkcję f(x)=4x^2-5x zapisz w postaci kanonicznej.
y=4x²-5x
a=4
b=-5
c=0
x(w)=-b/2a
x(w)=-(-5)/4·2=⁵/₈
Δ=b²-4ac
Δ=(-5)²-4·4·0=25
y(w)=-Δ/4a
y(w)=-25/4·4=-1⁹/₁₆
y=a(x-p)²+q
y=4(x-⁵/₈)²-1⁹/₁₆
postać kanoniczna:
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y=4x²-5x
a=4
b=-5
c=0
x(w)=-b/2a
x(w)=-(-5)/4·2=⁵/₈
Δ=b²-4ac
Δ=(-5)²-4·4·0=25
y(w)=-Δ/4a
y(w)=-25/4·4=-1⁹/₁₆
y=a(x-p)²+q
y=4(x-⁵/₈)²-1⁹/₁₆
postać kanoniczna: