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y=-3x^2+ax+2
nilai ektrim x=1
nilai a & nilai maksimum?
x=-b/2a
1=-(a)/2.-3
1=-a/-6
1x-6=-a
-6=-a
-6/-1=a
6=a
----
y=-3x^2+6x+2
y=D/-4a
=b^2-4ac/-4.a
=6^2-4.-3.2/-4.-3
=36+24/12
=60/12
=5
----
Jadi titik puncak koordinat ={1,5}
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