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substitusi saja buat cari range:
h(-3) = 3 - (-3)² = - 6
h(-2) = 3 - (-2)² = - 1
h(-1) = 3 - (-1)² = 2
h(0) = 3 - (0)² = 3
h(1) = 3 - 1² = 2
h(2) = 3 - 2² = - 1
h(3) = 3 - 3² = - 6
substitusi nilai daerah asal ke h(x), diperoleh:
h(-3) = 3 - (-3)² = - 6
h(-2) = 3 - (-2)² = - 1
h(-1) = 3 - (-1)² = 2
h(0) = 3 - (0)² = 3
h(1) = 3 - 1² = 2
h(2) = 3 - 2² = - 1
h(3) = 3 - 3² = - 6
Jadi, daerah hasilnya adalah {-6, -1, 2, 3}