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f(x) = x √(9 - x)
untuk mendapatkan turunan pertamanya, gunakan chain's rule :
f ' (x) = √(9 - x) + x (-1/2√9 - x)
f ' (x) = √(9 - x) - x / 2√(9-x)
√(9-x) - x/(2√(9 -x)) < 0
(2(9 - x) - x)/(2√(9-x)) < 0
(-3x + 18)/(2√(9-x)) < 0
pembuat nol :
-3x + 18 = 0 --------> x = 6
syarat : 9-x > 0
x - 9 < 0
x < 9
buat garis bilangan :
------------(6)-----SOLUSI---------(9)--------------
so, solusinya = 6 < x < 9, x∈ real