" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
f(-3) = -15 --> -3a + b = -15
f(3) = -9 --> 3a + b = -9 +
2b = -24 --> b = -12
3a - 12 = -93
a = -9 + 12
3a = 3
a=1
f(x) = x - 12
f(-2) + f(2) = (-2 -12) + (2 - 12) = -14 -10 = -24
f(-3) = -15
f(3) = -9
MAKA:
f(x) = ax + b
f(-3) = a.-3 + b
-15 = -3a + b Persamaan 1
f(x) = ax + b
f(3) = a.3 + b
-9 = 3a +b Persamaan 2
jadi kedua persamaan dikurangkan :
(-15 = -3a + b) - (-9= 3a +b)
-6 = -6a
a = 1
mencari Nilai b :
masukkan salah satu persamaan :
-3a + b = -15
-3.1 + b = -15
-3 +b = -15
b = -15 + 3 = -12
jadi :
f(-2) + f(2)
untuk F(2) :
ax + b
1.-2 + (-12) = -14
Untuk f(2):
ax + b
1.2 + (-12) = -10
Jadi : f(-2) + F(2) = (-14)+ (-10) = (-24)