Question

Fungsi f ditentukan dengan f(x)=px+q,jika f(1)=4,dan f(-2)=1
a.tentukan nilai P dan Q
b.rumus fungsi

Answer 1

F(x) = px+q
f(1) = 4
= p.1+q = 4
= p + q = 4
f(-2) = 1
= p.-2+q = 1
= -2p + q = 1
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
p + q = 4
-2p + q = 1
-----------------  -
3p = 3
p = 3/3
p = 1
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
p + q = 4
1 + q = 4
q = 4 - 1
q = 3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
a. Nilai p = 1 dan nilai q = 3
b. Rumus fungsi -> f(x) = x + 3

{Maaf kalau salah}

Answer 2

F(x)= px+q
~f(1)= p(1) +q
   4 = 1p + q ---> pers 1
~f(-2)=p(-2) +q
   1= -2p+q ----> pers 2

~pers1 4 = 1p + q
~pers2 1 = -2p+ q   
          3 = 3p 
          p = 3
                 3
           p=1

~pers 1 = 4 = 1p +q
               4 = 1.1 +q
               4=   1+q
               q = 4-1
               q = 3
Jadi P = 1 ,, Q =3