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g o f = g[f(x)]
g[f(x)] = [(3X + 2) + 3]/[2(3X + 2) + 1]
g[f(x)] = [3X + 5]/[6X + 4 + 1]
g[f(x)] = [3X + 5]/[6X + 5]
f o g: f[g(x)]
f[g(x)] = 3[(X + 3)/(2X + 1)] + 2
3[(X + 3)/(2X + 1)] = [(3X + 9)/(2X + 1)] + 2
[(3X + 9)/(2X + 1)] + 2/1 = [(3X + 9) + 2(2X + 1)]/[2X + 1]
[(3X + 9) + (4X + 2)]/[2X + 1]
[3X + 9 + 4X + 2]/[2X + 1]
[7X + 11]/[2X + 1]
f[g(x)] = [7X + 11]/[2X + 1]