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x² + y² = 1
rasio = √1 = 1
maka, batas rasio :
0 ≤ r ≤ 1
karena lingkaran penuh, maka batas sudutnya :
0 ≤ θ ≤ 2π
z = 1 + x² + y²
fx = 2x
(fx)² = 4x²
fy = 2y
(fy)² = 4y²
sehingga, luas permukaannya adalah :