Question

Favor colaboren me en factorizar los siguientes polinomios
3a-12ab
2ab+2ac+2ad
x(y+1) - 3(y+1)
a(b-1)+ c(b-1)
m(a-c)+a-c
b(a+1) - a -1
1 - b + 2a(1-b)
(a + 3) (a+1) - 4(a+1)
m(n - 2) +2 -n
(1 +3n)(m + 1) -2n(m + 1) + 3(m + 1)
c(x - 3y) + d(3y - x)

Answer 1

3a-12ab= 3a(1-4b)
2ab+2ac+2ad= 2a(b+c+d)
x(y+1) - 3(y+1) =  (y+1) (x -3)
a(b-1)+ c(b-1) = (b-1)(a+c)
m(a-c)+a-c = (a-c)(m+1)
b(a+1) - a -1 = b(a+1) - (a +1) = (a+1) (b -1)
1 - b + 2a (1-b) = (1-b)(1+2a)
(a + 3) (a+1) - 4(a+1)=(a+1)(a+3-4)= (a+1)(a-1)
m(n - 2) +2 -n=m(n - 2) -(n-2)= (n - 2) (m-1)
(1 +3n)(m + 1) -2n(m + 1) + 3(m + 1)=(m + 1) (1+3n-2n + 3)=(m + 1) (4+n)
c(x - 3y) + d(3y - x) =c(x - 3y) - d(x-3y ) = (x - 3y) (c - d) =