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CARANYA :
3x²-13x-10
-15×2=(-10)×3=(-30)
-15+2=-13
JADI,3x²-13x-10=3x²-15x+2x-10
=(3x²-15x)+(2x-10)
=3x(x-5)+2(x-5)
=(3x+2)(x-5)
rumus : ax²+bx+c = ax²+px+qx+c
dengan p×q=a×c,dan p+q=b