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= 6u^2 + 10u -16
= (6u +16)(u - 1)
a = 6
b= 10 (a. n +m)
c= -16. (n x m)
karena 2 faktor sekutu dr ketiganya. maka:
a. 2U + 6U - 20 = 2( U + 3U - 10)
untk faktor pengurangan
a dikali c, cari pasangan yg ketika dikurangi hasilnya b
b. 6U^2 + 10U - 16 = 6U^2 - 6u + 16u -16
= 3u(2u - 2) + 8 (2u - 2)
= ( 3u + 8)(2u - 2)
telaah kembali y :-)