Fahri akan membuat kotak berbentuk balok dengan perbandingan p:l:t=3:2:4.jika panjang kotak tersebut 15 cm, maka luas permukaan kotak adalah..?
5dregensleyer
Panjang = 15 3a = 15 a = 15/3 a = 5 p = 15 l = 2 x 5 = 10 t = 4 x 5 = 20 Luas permukaan Lp = 2 ( p x l + p xt + l x t ) = 2 ( 15 x 10 + 15 x 20 + 10 x 20 ) = 2 ( 150 + 300 + 200 ) = 2 ( 650 ) = 1300 cm³
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Alcander
X = 15/3 = 5 panjang kotak = 15 lebar kotak = 2 × 5 = 10 tinggi kotak = 4 × 5 = 20
3a = 15
a = 15/3
a = 5
p = 15
l = 2 x 5 = 10
t = 4 x 5 = 20
Luas permukaan
Lp = 2 ( p x l + p xt + l x t )
= 2 ( 15 x 10 + 15 x 20 + 10 x 20 )
= 2 ( 150 + 300 + 200 )
= 2 ( 650 )
= 1300 cm³
panjang kotak = 15
lebar kotak = 2 × 5 = 10
tinggi kotak = 4 × 5 = 20
Lp balok = 2( (p×l) + (p×t) + (l×t) )
= 2( (15×10) + (15×20) + (10×20)
=2( 150 + 300 + 200)
=2(650)
=1300