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de aqui resolvemos el dividendo primero =
A) [ π^-5 * π^-3 * π^6 ] ^2 = [ π^ ( -5 -3+6) ] ^2 = ( π^ -2) ^2 = π^ -4
B)π^5 * ( π1/2 / π^-3) = π^5 * ( π1/2 * π^ 3) = π^ ( 5+1/2+3) =π^ ( 17 /2)
ENTONCES NOS QUEDA HACI=
π^ ( -4 ) / π^ ( 17/2) = π^ ( -4 - 17/2 ) =π^ ( - 25/2 )