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(a+b+c)² = a²+b²+c²+2(ab+bc+ac)
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(2x-3y+1)² = (2x)²+(-3y)²+1²+2[(2x)(-3y)+(2x)(1)+(-3y)(1)]
(2x-3y+1)² = 4x²+9y²+1 + 2[-6xy + 2x - 3y]
(2x-3y+1)² = 4x²+9y²+1 + 2(-6xy) + 2(2x) + 2(-3y)
(2x-3y+1)² = 4x² + 9y² + 1 - 12xy + 4x - 6y >>>> Respuesta
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eso es todo , espero se entienda xD
SALUDOS!!