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Y = 2
7X + 6×2 = 2
7X = 2 - 12
X = - 10/7
X = - 10/7
Y = 2
7x + 6y = 2 .............(1)
y + 5 = 3 ..............(2)
El método es de sustitución:
Resolvemos y de (2):
y = 5 - 3
y = 2
Sustituimos en (1):
7x + 6(2) = 2
7x +12 = 2
7x = 2- 12
7x = - 10
x = - (10/7)
No será la ecuación (2) y+5x = 3 ????