Respuesta:
8. Hallar la ecuación
2(x - 6) + 8x = 3(2x + 4)
2(x) + 2(-6) + 8x = 3(2x) + 3(4)
2x + (-12) + 8x = 6x + 12
10x - 12 = 6x + 12
10x - 6x = 12 + 12
4x = 24
x = 24/4
x = 6
9. Hallar la ecuación
4(x - 8) + 5x = 2(5x + 4)
4(x) + 4(-8) + 5x = 2(5x) + 2(4)
4x + (-32) + 5x = 10x + 8
9x - 32 = 10x + 8
9x - 10x = +8 +32
-x = 40
x = -40
10. Si 03 correctores cuestan S/.10, ¿Cuánto costarán 36 correctores?
3/10 = 36/x
3x = 10(36)
3x = 360
x = 360/3
x = 120
36 correctores costarán S/.120
11. Si 03 lapiceros finos cuestan S/.5, ¿Cuánto costarán 60 lapiceros?
3/5 = 60/x
3x = 5(60)
3x = 300
x = 300/3
x = 100
60 lapiceros costarán S/.100
Explicación paso a paso:
Espero te sirva
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Verified answer
Respuesta:
8. Hallar la ecuación
2(x - 6) + 8x = 3(2x + 4)
2(x) + 2(-6) + 8x = 3(2x) + 3(4)
2x + (-12) + 8x = 6x + 12
10x - 12 = 6x + 12
10x - 6x = 12 + 12
4x = 24
x = 24/4
x = 6
9. Hallar la ecuación
4(x - 8) + 5x = 2(5x + 4)
4(x) + 4(-8) + 5x = 2(5x) + 2(4)
4x + (-32) + 5x = 10x + 8
9x - 32 = 10x + 8
9x - 10x = +8 +32
-x = 40
x = -40
10. Si 03 correctores cuestan S/.10, ¿Cuánto costarán 36 correctores?
3/10 = 36/x
3x = 10(36)
3x = 360
x = 360/3
x = 120
36 correctores costarán S/.120
11. Si 03 lapiceros finos cuestan S/.5, ¿Cuánto costarán 60 lapiceros?
3/5 = 60/x
3x = 5(60)
3x = 300
x = 300/3
x = 100
60 lapiceros costarán S/.100
Explicación paso a paso:
Espero te sirva