[tex]b = \frac{55 - 25}{11 - 1} = \frac{30}{10} = 3 \\ \\ u45 = u11 + 34b \\ u45 = 55 + 34(3) \\ u45 = 55 + 102 \\ u45 = 157 \: (A)[/tex]
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[tex]b = \frac{55 - 25}{11 - 1} = \frac{30}{10} = 3 \\ \\ u45 = u11 + 34b \\ u45 = 55 + 34(3) \\ u45 = 55 + 102 \\ u45 = 157 \: (A)[/tex]