" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
x+2 = 1 ..............2(x+2)=1(y+1)........2x+4=y+1......2x-y=1-4.......2x-y= -3
y+1 2
x+1 = 3 .............5(x+1)=3(y-2)..........5x+5=3y-6....5x-3y= -6-5.....5x-3y= -11
y-2 5
ahora hacemos reduccion.
-3(2x-y= -3)............-6x+3y=9
5x-3y= -11.............5x-3y= -11
-x= -2...................x=2
si x=2
2x-y= -3
2(2)-y= -3
4-y= -3
-y= -3-4
-y= -7
y=7
la fraccion que buscamos es: 2
7