Tenemos. De la figura Area Fig1 = Area de la circulo de radio 4 /4 Area fig2 = Area del rectángulo ABCD AreaFig3 = 3/4 del area del riculo de radio 2 BC = 2m + 4m = 6m Area Total = πR²/4 + (6 * 8) + 3/4(πr²) Area total = π(4m)²/4 + 48 + 3/4(π(2)²)Area total = 16π/4 + 48+ 3/4(π4) Area total = 4π + 48 + 3π Area total = 7π + 48 Respuesta. El area total = 48 + 7π
Tenemos.
De la figura
Area Fig1 = Area de la circulo de radio 4 /4
Area fig2 = Area del rectángulo ABCD
AreaFig3 = 3/4 del area del riculo de radio 2
BC = 2m + 4m = 6m
Area Total = πR²/4 + (6 * 8) + 3/4(πr²)
Area total = π(4m)²/4 + 48 + 3/4(π(2)²)Area total = 16π/4 + 48+ 3/4(π4)
Area total = 4π + 48 + 3π
Area total = 7π + 48
Respuesta.
El area total = 48 + 7π