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x hombres_ y mujeres
3x/y=5
Despejas x -> 5y/3=x
x+10 hombres _y+8 mujeres
3 hombres_____ 2 mujeres
[3*(y+8)]/2= x+10
Reemplazas x -> [3*(y+8)]/2= 5y/3+10
3y+24=10/3 y +20
24-20= 10/3y-3y
4=1/3y
y=12
x= 5y/3
x=20
Inicialmente había 12 mujeres y 20 hombres.
20/12= 5/3
(20+10)/(12+8)= 30/20= 3/2