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a1 = 3, r = 2 y an = 96
Hallando el termino "n"
an = a1 . rⁿ⁻¹
96 = 3 . 2ⁿ⁻¹
96/3 = 2ⁿ⁻¹
32 = 2ⁿ⁻¹
2 . 2 . 2 . 2 .2 = 2ⁿ⁻¹
2⁵ = 2ⁿ⁻¹
5 = n - 1
5 + 1 = n
6 = n
Entonces el termino que vale 96 es el sexto termino