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4c₊2g=100
Por el metodo del rombo
40ₓ4-100
------------
4-2
160-100
------------
2
60
---------
2
30 gallinas ∴ Hallamos el total de conejos
40-30=10 conejos
Rpta: Hay 10 conejos
4C+ 2G = 100 ......... II
-2C-2G = -80
4C+ 2G = 100
''''''''''''''''''''''''''''''''''
2C = 20
C = 20/2
C = 10
HAY 10 CONEJOS