EN UNA FIGURA ,LOS LADOS A Y B SUMAN 30 CMS.LOS LADOS B YC SUMAN 41 CM Y LOS LADOS AY C SUMAN 37.¿CUANTO MIDE CADA LADO DEL TRIANGULO?
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a+b=30 por existencia de triangulos determinas: a<41
b+c=41 b<37
a+c=37 c<41
luego resuelves el sistema
a+b+c=54 como a+b=30....c=24,a=13,b=17
A + B = 30
B + C = 41
A + C = 37
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2A + 2B + 2C = 108
A + B + C = 54
Entonces si A + B = 30
A + B + C = 54
30 + C = 54
C = 54 - 30
C = 24
A + B + C = 54
A + 41 = 54
A = 54 - 41
A = 13
A + B + C = 54
B + 37 = 54
B = 54 - 37
B = 17