Respuesta:
piden volumen del cono
primero, hallamos la altura. Por Pitágoras
[tex]h = \sqrt{13 {}^{2} - {5}^{2} } = 12[/tex]
[tex]volumen = \frac{\pi {r}^{2}h }{3} \\ = \frac{(3.14)( {5}^{2})(12) }{3} \\ = 314 {cm}^{3} [/tex]
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Verified answer
Respuesta:
piden volumen del cono
primero, hallamos la altura. Por Pitágoras
[tex]h = \sqrt{13 {}^{2} - {5}^{2} } = 12[/tex]
[tex]volumen = \frac{\pi {r}^{2}h }{3} \\ = \frac{(3.14)( {5}^{2})(12) }{3} \\ = 314 {cm}^{3} [/tex]