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T2.cos 20 - T1.cos 40 = 0
T2.cos 20 = T1.cos 40
T2 = T1.cos 40 / cos 20
T2 = T1.(0,82) ____ Ecuacion (1)
ΣFy = 0
T1.sen 40 + T2.sen 20 - 2 = 0
0,6427T1 + 0,342T2 = 2 .. ____ Ecuacion (2)
Reemplazar ecuacion (1) en (2)
0,64T1 + 0,34T2 = 2
0,64T1 + 0,34 * T1.(0,82) = 2
0,64T1+ 0,28T1 = 2
0,92T1 = 2
T1 = 2 / 0,92
T1 = 2,17 kN
Reemplazar T1 en (1)
T2 = T1.(0,82)
T2 = (2,17)*(0,82)
T2 = 1,78 kN