|AB| = pierwiastek z (-5-(-1))^2+(5-(-2)^2
|AB| = pierwiastek z (-5+1))^2+(5+2)^2
|AB| = pierwiastek z (-4)^2+(7)^2
|AB| = pierwiastek z 16+49
|AB| = pierwiastek z 65
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masz taki wzór:
d=√(x₂-x₁)²+(y₂-y₁)²
|AB| = pierwiastek z (-5-(-1))^2+(5-(-2)^2
|AB| = pierwiastek z (-5+1))^2+(5+2)^2
|AB| = pierwiastek z (-4)^2+(7)^2
|AB| = pierwiastek z 16+49
|AB| = pierwiastek z 65
A(xA,yA)
B(xB,yB)
AB=√[(xA-xB)²+(yA-yB)²]
xA=-1
yA=-2
xB=-5
yB=5
AB=√[(-1-(-5))²+(-2-5)²]=√[(-1+5)²+(-7)²]=√(4²+49)=√(16+49)=√65