Respuesta:
[tex]\mathrm{a\:coordenadas\:polares}:\quad \left(2\sqrt{5},\:-\arctan \left(\frac{1}{2}\right)+2\pi \right)[/tex]
Explicación paso a paso:
[tex]Angulo=\arctan \left(\frac{-2}{4}\right)[/tex]
[tex]r=2\sqrt{5}[/tex]
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Verified answer
Respuesta:
[tex]\mathrm{a\:coordenadas\:polares}:\quad \left(2\sqrt{5},\:-\arctan \left(\frac{1}{2}\right)+2\pi \right)[/tex]
Explicación paso a paso:
[tex]Angulo=\arctan \left(\frac{-2}{4}\right)[/tex]
[tex]r=2\sqrt{5}[/tex]
[tex]\mathrm{a\:coordenadas\:polares}:\quad \left(2\sqrt{5},\:-\arctan \left(\frac{1}{2}\right)+2\pi \right)[/tex]