La concentración molar de la solución es : 0.157 M .
La concentración molar de la solución se calcula en base a la concentración [H+] y la de [OH- ] de la siguiente manera :
Ph = 10.52
Kb= 7*10-7
Concentración molar = M =?
Ph = - Log [ H⁺] se despeja : [H⁺]
[ H⁺ ] = antilog (- Ph ) = antilog(- 10.52 )
[ H⁺ ] = 3.0199*10-11
POH = 14 - Ph = 14 -10.52 = 3.48
POH = - Log[ OH⁻]
[ OH ⁻] = antilog ( - POH) = antilog( - 3.48 ) = 3.3113*10-4
[OH⁻] = √( Kb* [ sol base] )
Se despeja [ sol base ] :
[ sol base ] = [OH⁻]² / Kb = ( 3.3113*10-4)²/ 7*10-7
[ sol base ] = 0.157
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Verified answer
La concentración molar de la solución es : 0.157 M .
La concentración molar de la solución se calcula en base a la concentración [H+] y la de [OH- ] de la siguiente manera :
Ph = 10.52
Kb= 7*10-7
Concentración molar = M =?
Ph = - Log [ H⁺] se despeja : [H⁺]
[ H⁺ ] = antilog (- Ph ) = antilog(- 10.52 )
[ H⁺ ] = 3.0199*10-11
POH = 14 - Ph = 14 -10.52 = 3.48
POH = - Log[ OH⁻]
[ OH ⁻] = antilog ( - POH) = antilog( - 3.48 ) = 3.3113*10-4
[OH⁻] = √( Kb* [ sol base] )
Se despeja [ sol base ] :
[ sol base ] = [OH⁻]² / Kb = ( 3.3113*10-4)²/ 7*10-7
[ sol base ] = 0.157