Respuesta:
[tex]21m[/tex] por [tex]49m[/tex]
Explicación paso a paso:
[tex]Ancho: a[/tex]
[tex]Largo: L = \frac{7}{3} a[/tex]
[tex]Perimetro: P = 140m[/tex]
Ecuación:
[tex]P= 2(ancho ) + 2 (largo)[/tex]
[tex]140m = 2(a) + 2(\frac{7a}{3} )[/tex]
[tex]Multiplicamos -por- (3).[/tex]
[tex]3 ( 140m = 2a + \frac{14a}{3} )[/tex]
[tex]420m = 6a+ 14a[/tex]
[tex]420m = 20a[/tex]
[tex]\frac{420m}{20} = a[/tex]
[tex]a = 21m[/tex]
[tex]L= \frac{7}{3} a = \frac{7}{3}(21m) = 7(7m)[/tex]
[tex]L = 49m[/tex]
Las dimensiones del terreno son:
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Respuesta:
[tex]21m[/tex] por [tex]49m[/tex]
Explicación paso a paso:
[tex]Ancho: a[/tex]
[tex]Largo: L = \frac{7}{3} a[/tex]
[tex]Perimetro: P = 140m[/tex]
Ecuación:
[tex]P= 2(ancho ) + 2 (largo)[/tex]
[tex]140m = 2(a) + 2(\frac{7a}{3} )[/tex]
[tex]Multiplicamos -por- (3).[/tex]
[tex]3 ( 140m = 2a + \frac{14a}{3} )[/tex]
[tex]420m = 6a+ 14a[/tex]
[tex]420m = 20a[/tex]
[tex]\frac{420m}{20} = a[/tex]
[tex]a = 21m[/tex]
[tex]L= \frac{7}{3} a = \frac{7}{3}(21m) = 7(7m)[/tex]
[tex]L = 49m[/tex]
Las dimensiones del terreno son:
[tex]21m[/tex] por [tex]49m[/tex]