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log((x-9)*(50x))=3
log(50x^2-450x)=3
aplicamos propiedad : log x=y 10^y=x
10^3= 50x^2-450x
50x^2-450x-1000=0
div por 50
x^2-9x-20=0
resolvemos la e. de 2º grado
y nos da : x= 10.8 x=-1,84