Ecuaciones en una variable xfa
3(4x-4) +2 (2x+10)= 15
5(2x-3) +6= 4(5x-4) +8
3(4x-4) +2 (2x+10)= 15
5(2x-3) +6= 4(5x-4) +8
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Respuesta:3(4 × -4) + 2(2 × 10 +