Dział wyrażeń wymiernych
rozwiąż równiania:
a)
b)
(2x-3) * 3 = (4x+1) * 5
6x - 9 = 20x + 5
14x = -14
x = -1
(x-1)(x+5) = -5(x+1)
x^2 + 4x - 5 = -5x - 5
x^2 + 9x = 0
x(x+9) = 0
x=0 v x=-9
a. 5(4x+1)=3(2x-3)
20x+5=6x-9
20x-6x=-9-5
14x=-14 |:14
x=-1
b.
(x+5)(x-1)=-5(x+1)
x²-x+5x-5=-5x-5
x²+4x+5x=-5+5
x²+9x=0
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a)
(2x-3) * 3 = (4x+1) * 5
6x - 9 = 20x + 5
14x = -14
x = -1
b)
(x-1)(x+5) = -5(x+1)
x^2 + 4x - 5 = -5x - 5
x^2 + 9x = 0
x(x+9) = 0
x=0 v x=-9
a. 5(4x+1)=3(2x-3)
20x+5=6x-9
20x-6x=-9-5
14x=-14 |:14
x=-1
b.
(x+5)(x-1)=-5(x+1)
x²-x+5x-5=-5x-5
x²+4x+5x=-5+5
x²+9x=0