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y = {cos(3x - 2)}²
y ' = 2cos(3x - 2)(-sin(3x - 2))(3)
= -3(2sin(3x - 2)cos(3x -2))
= -3Sin2(3x - 2)
= -3sin(6x - 4)
b. y = sin^2 (2-x) = {sin(2 - x)}²
y ' = 2{sin(2 - x)(cos(2 - x)(-1)}
= -2sin(2 - x)cos(2 - x)
= - Sin2(2 - x)
= -Sin(4 - 2x)
c. y = x^2 sin 3x
y '= 2xsin3x + x²(cos3x)3
= 2sin3x + 3x²cos3x
d. y = x^2 cos 2x
y ' = 2xcos2x + x²(-sin2x)2
= 2xc0s2x - 2x²sin2x