Question

Dy/dx +4y =8, y (0)=1
tolong dibantu jawab​

Answer 1

dy/dx +4y =8, y (0)=1

dy/dx =-4y+ 8

dy=(8-4y)dx

1/(8-4y)dyed=0

misal u=(8-4y)

du=-4dy

dy=-¼du

1/(8-4y)-(-¼)d(8-4y)-dx=0

-¼ln 1/(8-4y)-x=c

-¼ln 1/(8-4*1)-0=c

c=-¼ln 1/(8-4*1)

=¼ln (4)

=½ln2