Dy/dx +4y =8, y (0)=1
tolong dibantu jawab
tolong dibantu jawab
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dy/dx +4y =8, y (0)=1
dy/dx =-4y+ 8
dy=(8-4y)dx
1/(8-4y)dyed=0
misal u=(8-4y)
du=-4dy
dy=-¼du
1/(8-4y)-(-¼)d(8-4y)-dx=0
-¼ln 1/(8-4y)-x=c
-¼ln 1/(8-4*1)-0=c
c=-¼ln 1/(8-4*1)
=¼ln (4)
=½ln2