Question

Dwa zadania w załącznikach. Na dzisiaj.

Answer 1

9.
(sin210°-cosπ/3)*cos330° = (sin(180°+30°)-1/2)*cos(360°-30°)=
(-sin30°-1/2)*cos30°=(-1/2-1/2)*√3/2 = -√3/2
10.
(cos240°-sin(π/6))*sin300°=(cos(180°+60°)-1/2)*sin(360°-60°)=
(-cos60°-1/2)*(-sin60°)=(-1/2-1/2)*(-√3/2)= √3/2