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f=10-30%*10=10-0,3*10=10-3=7cm
P=ef/2
P=10*7/2=5*7=35cm^2 pole rombu
dluzsza przekatna rombu x=10cm
krotsza przekatna y=x-30%x=x-0,3x=0,7x=0,7·10=7cm
pole rombu wynosi zatem
P=1/2·x·y=1/2·10·7=70/2=35 cm²